Politics and Police Administration Research Paper Example

Politics and Police Administration Introduction The system of appointing police varies across the world as it depends on the constitution governing a given country. Therefore, in some instances, police are appointed or recruited by a commission, a city council, and local chief executive or by other police departments. The term police also varies in accordance with the laws and regulations governing the police force. The appointing mechanism also differs on the position of the individual being sought. For instance, when appointing police bosses in various agencies, the government is highly involved.

Statistics Analysis Paper - 275 Words

Statistics Analysis Paper (Statistics Project Sample) Content: X1 X2 X2 X2 X3 X23 X4 X24 39.31 1545.2761 36.69 1346.1561 38.99 1520.2201 40.04 1603.2016 39.87 1589.6169 40 1600.0000 40.02 1601.6004 39.89 1591.2121 39.87 1589.6189 41.01 1681.8201 39.99 1599.2001 39.93 1594.4049 Sum SX1=119.05 SX21=4,724.5119 SX2=117.7 SX22=4,627.9762 SX3=119 SX23=4,721.0206 SX4=119.86 SX24=4,788.8186 (SX)2 14,172.9025 13,853.29 14,161 14,366.4196 QUESTION 1SSTOTAL= (4,724.5119+4,627.9762+4,721.0206+4,788.8186) à ¢Ã¢â€š ¬ (119.05+117.7+119+119.8)2 /12=18,862.3273- 18,845.65021=16.6770917SSAMONG= (14,172.9025/3 +13,853.29/3+14161/3+14,366.4196/3) - (119.05+117.7+119+119.8)2 /12=4,724.300833+4,617.763333+4,720.333333+4,788.806533- 18,845.65021=18,851.20403-18,845.65021=5.553822SSWITHIN=16.6770917-5.553822=11.1232697DF (among) =3Ms (among)=SSamong/3=5.553822/3=1.851274DF (within) =8Ms (within) =SSwithin /8=11.1232697/8=1.390408713F=ms among/ mswithin=1.851274/1.390408713=1.331460298F must be at least 1.3315 to reach alpha0.05.Therefo re there exists significant difference in the performance of the four grades of gas.QUWSTION 2F=Variation among sample means/variation within individual observation in the same sample Dispenser mean Standard deviation n A 203 3 10 B 205 6 9 MSG=3(203-204)2 +3(205-204)2 /1=6MSE= (4-1)32 +(4-1)62 /(19-2)=7.941176471F=6/7.941176471=0.755555555With the level of significance at 0.05, F is greater than the level of significance. Therefore the variability of dispenser B exceeds that of dispenser A.QUEASTION 3ENTRANCE FREQUENCY (x-mean) (x-mean)2 NORTH 135 10 100 EAST 145 20 400 SOUTH 115 -10 100 WEST 105 -20 400 TOTAL 500 1000 Mean=500/4=125H0: entrance are equally utilizedH1: entrances not equally utilized